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A word has (9) letters with two different letters each repeated (2) times. How many distinct arrangements are possible?शब्द अनुप्रयोग के (9) अक्षरों में दो-दो अक्षर समान हैं। अलग व्यवस्थाएं कितनी होंगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (90720)(90720)
Two groups are repeated (2) times each, so the number is (\frac{9!}{2!2!}=90720). In exams, put each repeated group factorial in the denominator.दो समूह (2) बार समान हैं, इसलिए संख्या (\frac{9!}{2!2!}=90720) है। परीक्षा में हर repeated group का factorial हर में रखें।
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