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Subjects
Class 11MathematicsPermutations and CombinationsPermutationsMedium
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In a row of (8) people, how many arrangements are possible if one particular person does not sit at either end?

Answer and explanation

Correct answer: (30240)

The particular person has (6) inner positions and the remaining people sit in (7!) ways. The total is (6\cdot7!=30240).

Related tags

PermutationsRestricted PositionSeatingPermutations And CombinationsMathematicsClass 11 Mcq
सुधार सुझाएँ / Earn

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10 more MCQs
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  2. 2An online form has 4 options for class, 3 options for section, and 5 options for subject. In how many ways can one complete selection of a class, a section, and a subject be made?
  3. 3How many (3)-digit numbers can be formed from digits (1,3,5,7,9) without repetition?
  4. 4A (3)-letter code is to be formed from (6) distinct letters. If repetition is not allowed, how many codes are possible?
  5. 5Three distinct prizes are to be awarded to seven students. No student can receive more than one prize. How many ways are possible?
  6. 6If \(\frac{(n+5)!}{(n+3)!}=210\), what is the value of \(n\)?
  7. 7What is the value of \(\frac{21!}{19!\cdot2!}-\frac{18!}{16!\cdot2!}\)?
  8. 8If \(\frac{(n+1)!}{(n-1)!}-\frac{n!}{(n-2)!}=24\), what is the value of \(n\)?
  9. 9What is the value of \(\frac{22!}{20!\cdot 2!}-\frac{21!}{20!}\)?
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