0 reads0 ratings0 helpful
A word has (8) letters in which one letter is repeated (2) times. How many distinct arrangements are possible?शब्द व्यवस्था के (8) अक्षरों में व अक्षर (2) बार आता है। अलग व्यवस्थाएं कितनी होंगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (20160)(20160)
One letter is repeated (2) times, so the number is (\frac{8!}{2!}=20160). In exams, divide by factorials of repeated letters.एक अक्षर (2) बार समान है, इसलिए संख्या (\frac{8!}{2!}=20160) होगी। परीक्षा में समान अक्षरों से भाग दें।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
