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How many (3)-digit even numbers can be formed from (0,2,4,6,8) without repetition?अंकों (0,2,4,6,8) से बिना पुनरावृत्ति (3) अंकों की कितनी सम संख्याएं बन सकती हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (48)(48)
All possible last digits are even, but the hundreds place cannot be (0). Total numbers are (4\cdot4\cdot3=48).सभी उपलब्ध अंतिम अंक सम हैं, पर सैकड़े में (0) नहीं हो सकता। कुल (4\cdot4\cdot3=48) संख्याएं बनेंगी।
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