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In how many ways can 8 distinct books be arranged in a row?

Answer and explanation

Correct answer: 40320

The governing concept is permutation: when distinct objects are placed in a row, their order matters, so all n objects can be arranged in n! ways. Here n = 8, and therefore the required number is 8! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 40320. Hence option A is correct. Option B, 5040, is 7!, which would arrange only seven objects. Option C, 720, is 6!, and option D, 56, is not the factorial count for a complete linear arrangement. Since every book is distinct and all eight are used, no repetition adjustment or combination formula is needed.

Related tags

PermutationsLinear ArrangementFactorialPermutations And CombinationsMathematicsClass 11 Mcq

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