0 reads0 ratings0 helpful
What will be the value of ({}^{12}P_{0}+{}^{12}P_{1})?({}^{12}P_{0}+{}^{12}P_{1}) का मान क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 1313
Using the permutation formula \({}^{n}P_r=\frac{n!}{(n-r)!}\), we get \({}^{12}P_0=1\) and \({}^{12}P_1=12\). Hence, \({}^{12}P_0+{}^{12}P_1=1+12=13\). Option 12 is only the value of \({}^{12}P_1\), not the required sum. Exam tip: always remember that \({}^{n}P_0=1\) for every \(n\).क्रमचय का सूत्र
\({}^{n}P_r=\frac{n!}{(n-r)!}\) है। अतः \({}^{12}P_0=1\) तथा \({}^{12}P_1=12\)। इसलिए \({}^{12}P_0+{}^{12}P_1=1+12=13\)। विकल्प 12 केवल \({}^{12}P_1\) का मान है, योग का नहीं। परीक्षा में याद रखें कि किसी भी \(n\) के लिए \({}^{n}P_0=1\) होता है।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
