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How many distinct arrangements are there for the word (DAD)?

Answer and explanation

Correct answer: (3)

The direct answer is option A, 3. The word DAD has 3 positions, but the two D letters are identical. If all three letters were different, there would be 3!=6 arrangements. However, interchanging the two D’s does not produce a visibly new word, so every distinct arrangement has been counted twice. Divide by 2!: 3!/2!=6/2=3. They are DAD, ADD, and DDA. Option A is correct. Option B, 6, incorrectly treats the repeated D letters as different. Option C, 2, misses one arrangement. Option D, 1, would be true only if there were no meaningful rearrangement, but three distinct placements are possible. The repeated-letter formula is n!/(r!), with one division for each repeated group. Memory cue: identical objects must not be labelled; divide by the factorial of their repetition count.

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PermutationsClass11Easy

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