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How many distinct words can be formed using all letters of TRAIN?

Answer and explanation

Correct answer: 120

The relevant concept is permutation of distinct letters. TRAIN has five letters—T, R, A, I, and N—and no letter is repeated. When all five letters are used, the first position can be selected in 5 ways, the second in 4 ways, and the remaining positions in 3, 2, and 1 ways. Therefore, the total number of different arrangements is 5 × 4 × 3 × 2 × 1 = 5! = 120. Hence option C is correct. No repeated-letter denominator is needed because every letter is distinct. The value 60 leaves out half of the arrangements, 25 is not the factorial count, and 10 does not represent the number of possible orders. The question asks for arrangements, so combinations would ignore order and be unsuitable.

Related tags

PermutationsWord FormationDistinct LettersClass 11Permutations And CombinationsMathematicsClass 11 Mcq

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