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How many total ways are there to arrange 7 different certificates in a row?

Answer and explanation

Correct answer: 5040

The governing concept is permutation in a linear arrangement. Since all seven certificates are distinct and every certificate must be used, the order of the certificates matters. For the first position there are 7 choices, for the second 6 remaining choices, then 5, 4, 3, 2, and 1. By the multiplication principle, the total number of arrangements is 7 × 6 × 5 × 4 × 3 × 2 × 1 = 7! = 5040. Therefore, option A is correct. Option B is 6!, so it effectively omits one object. Option D is 5!, and option C is only 7², neither of which counts all possible linear orders. A combination formula is inappropriate because the certificates are being arranged, not merely selected.

Related tags

PermutationsFactorialLinear ArrangementClass 11Permutations And CombinationsMathematicsClass 11 Mcq

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