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In a delivery code, the first (3) positions contain distinct letters chosen from (8) available letters and the last (3) positions contain digits from (0) to (9). If exactly one (0) must appear in the last (3) digits, how many codes are possible?

Answer and explanation

Correct answer: (8\cdot7\cdot6\cdot3\cdot9^2)

The letters can be chosen in (8\times7\times6) ways and the position of (0) can be chosen in (3) ways. The remaining two digits have (9^2) choices.

Related tags

PermutationsCombinationsCounting PrincipleClass 11ExpertFundamental Principle Of CountingPermutations And CombinationsMathematics

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