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Subjects
Class 11MathematicsPermutations and CombinationsFundamental principle of countingExpert
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A (5)-digit code is formed using (1,2,3,4). Each digit must appear at least once. How many such codes are possible?

Answer and explanation

Correct answer: (240)

One digit appears twice and the others appear once each. The repeated digit has (4) choices and arrangements are (5!/2!), giving (240).

Related tags

PermutationsCombinationsCounting PrincipleClass 11ExpertFundamental Principle Of CountingPermutations And CombinationsMathematics
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