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Class 11MathematicsPermutations and CombinationsFundamental principle of countingExpert
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A train ticket requires choosing (1) coach type, (1) seat type, and (1) meal option. The numbers of options are (4,3,5). If sleeper coach has only (2) meal options and the other (3) coaches have all (5) options, how many ticket combinations are possible?

Answer and explanation

Correct answer: (51)

Sleeper gives (1\times3\times2=6) ways and the other coaches give (3\times3\times5=45) ways. The total is (51).

Related tags

PermutationsCombinationsCounting PrincipleClass 11ExpertFundamental Principle Of CountingPermutations And CombinationsMathematics
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