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A question paper has (3) sections. A student must choose (2) questions from the first section with order, (1) from the second, and (1) from the third. The sections have (5,6,4) questions. How many ways are possible?

Answer and explanation

Correct answer: 480

The number of ordered selections of two questions from the first section is \(^{5}P_{2}=5\times4=20\). The second and third sections provide \(6\) and \(4\) choices respectively. By the multiplication principle, the total number of ways is \(20\times6\times4=480\). Option 240 would result from not treating the order of the first two questions as distinct. Exam tip: Use permutations, not combinations, whenever order matters.

Related tags

Fundamental Counting PrinciplePermutationsOrdered SelectionClass 11 MathematicsQuestion SelectionFundamental Principle Of CountingPermutations And CombinationsMathematics

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