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Class 11MathematicsPermutations and CombinationsFundamental principle of countingExpert
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In a (4)-place locker code, each place can contain a digit from (1,2,3,4,5,6). Exactly (2) places must contain (6). How many codes are possible?

Answer and explanation

Correct answer: (150)

Choose the positions of (6) in (\binom{4}{2}) ways, and the remaining (2) positions have (5^2) choices. The total is (\binom{4}{2}5^2=150).

Related tags

PermutationsCombinationsCounting PrincipleClass 11ExpertFundamental Principle Of CountingPermutations And CombinationsMathematics
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