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A website PIN has (5) digits. The first digit cannot be zero and exactly (2) positions must contain even digits. How many such PINs are possible?

Answer and explanation

Correct answer: (34000)

Split cases according to whether the first position is even or odd: (4\binom{4}{1}5\cdot5^3+5\binom{4}{2}5^2\cdot5^2=34000). Case division is safest for such restrictions.

Related tags

PermutationsCombinationsCounting PrincipleClass 11ExpertFundamental Principle Of CountingPermutations And CombinationsMathematics

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