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Class 11MathematicsPermutations and CombinationsFundamental principle of countingExpert
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A (6)-letter code has letters from (M,N,O) in the first (2) positions and letters from (P,Q,R,S) in the last (4) positions. The first (2) positions have no repetition, while repetition is allowed in the last (4) positions. How many codes are possible?

Answer and explanation

Correct answer: (3 \times 2 \times 4^4=1536)

The first block has (3) and (2) choices, and each position in the last block has (4) choices. Keep the conditions of different blocks separate.

Related tags

CountingLettersBlock-CodeFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq
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