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A train ticket code has (1) zone, (1) class, and (2) digits. There are (4) zones. If the zone is North, there are (3) class choices; for the other (3) zones, there are (5) class choices. Digits may repeat. How many codes are possible?

Answer and explanation

Correct answer: (1 \times 3 \times 10^2+3 \times 5 \times 10^2=1800)

Class choices depend on the zone, so count North and other zones separately. For digits with repetition, the factor remains (10^2).

Related tags

CountingTicketDependent-ChoiceFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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