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A (5)-digit number must contain exactly (2) digits equal to (7), and the remaining (3) positions may contain any digit from (0) to (9) except (7). The first digit cannot be (0). How many numbers are possible?

Answer and explanation

Correct answer: (4 \times 9^3+6 \times 8 \times 9^2)

Count separately whether the first digit is (7) or not. For exactly (2) occurrences, choose positions carefully.

Related tags

CountingDigitsExact-OccurrenceFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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