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A (4)-stage machine setting has (3) choices at the first stage. If the third option is chosen first, the second stage has (2) choices; otherwise it has (5) choices. The third and fourth stages have (4) and (6) choices respectively. How many settings are possible?

Answer and explanation

Correct answer: (1 \times 2 \times 4 \times 6+2 \times 5 \times 4 \times 6=288)

The second-stage choices depend on the first selection, so separate the (1) and (2) first-stage cases. When dependence appears, use cases.

Related tags

CountingMachineDependent-StagesFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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