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In a (6)-digit number, the first (2) digits must be the same and the last (4) digits can be any digits from (0) to (9). The first digit cannot be (0). How many numbers are possible?

Answer and explanation

Correct answer: (9 \times 1 \times 10^4)

The first digit is chosen in (9) ways and the second is fixed by it. A forced position has (1) choice.

Related tags

CountingDigitsForced-PositionFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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