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Subjects
Class 11MathematicsPermutations and CombinationsFundamental principle of countingExpert
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In a (5)-position seating code, each position is filled with one of (A,B,C). Consecutive (A)'s are not allowed only in the first two positions. How many codes are possible?

Answer and explanation

Correct answer: (3^5-3^3=216)

From all (3^5) codes, subtract the (3^3) codes having (AA) in the first two positions. Subtract only the forbidden part.

Related tags

CountingCodesComplementFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq
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