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In a (5)-digit secret number, the first digit is from (1) to (9), the second digit must be greater than the first, and the remaining (3) digits may be any digits. Repetition is allowed. How many numbers are possible?

Answer and explanation

Correct answer: (36 \times 10^3)

The first two digits form an increasing pair in (36) ways. The remaining (3) positions independently give (10^3) choices.

Related tags

CountingDigitsInequalityFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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