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In (5) empty positions, (2) distinct red balls, (1) blue ball, and (2) blank marks are to be placed. The red balls are counted distinctly and the blue ball is distinct. How many patterns are possible?

Answer and explanation

Correct answer: (5 \times 4 \times 3=60)

Choose positions for the two distinct red balls and then the blue ball, giving (5,4,3) choices. Blank marks occupy the remaining positions automatically.

Related tags

CountingArrangementPositionsFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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