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A (3)-stage process has (4) choices at the first stage. If the first selected choice is a special one, the second stage has (5) choices, otherwise each of the remaining (3) first choices gives (2) choices. The third stage always has (6) choices. How many outcomes are possible?

Answer and explanation

Correct answer: (1 \times 5 \times 6+3 \times 2 \times 6=66)

The second-stage choices depend on the first choice, so cases must be separated. Do not use one uniform product for dependent stages.

Related tags

CountingDependent-CasesStagesFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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