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A menu has (4) soups, (5) main dishes, and (3) desserts. A customer may take soup with main dish, main dish with dessert, or all three. How many meal choices are possible?

Answer and explanation

Correct answer: (4 \times 5+5 \times 3+4 \times 5 \times 3=95)

There are three separate cases and their results are added. Within each case the choices are multiplied.

Related tags

CountingCasesMenuFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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