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A secure locker code has (5) symbols. The first symbol is chosen from (4) special signs, the last from (3) colors, and the middle (3) symbols from (8) digits without repetition. How many codes are possible?

Answer and explanation

Correct answer: (4 \times 8 \times 7 \times 6 \times 3)

The middle three digits cannot repeat so their choices are (8,7,6). Multiply the boundary choices as well.

Related tags

CountingLockerRestricted-PositionsFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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