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A paper has three sections. Choose one question from two in the first section, two questions from four in order in the second section, and one question from three in the third section. How many answer sequences are possible?

Answer and explanation

Correct answer: 2 × 4 × 3 × 3 = 72

Use the fundamental principle of counting: when successive choices are independent, multiply the number of choices at each stage. The first section contributes 2 choices because one question is selected from 2. In the second section, order matters, so the number of ordered selections of 2 questions from 4 is 4P2 = 4 × 3 = 12. The third section contributes 3 choices. Hence the total is 2 × 12 × 3 = 2 × 4 × 3 × 3 = 72, so option A is correct. Option B incorrectly uses 4C2, option C omits the ordering factor, and option D counts four choices twice.

Related tags

Fundamental Principle Of CountingPermutationsOrdered SelectionPermutations And CombinationsMathematicsClass 11 Mcq

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