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From (9) students, a debate team of (4) is to be formed, and (2) speakers are to be chosen in order from that team. One particular student must be in the team but must not be a speaker. How many ways are possible?

Answer and explanation

Correct answer: (420)

Choose the other (3) team members from (8), then choose the ordered speakers from those (3) members. Fix the compulsory but ineligible member first.

Related tags

Team-SelectionSpeakersRestrictionFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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