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Class 11MathematicsPermutations and CombinationsFundamental principle of countingExpert
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Using digits (0,1,2,3,4,5,6,7,8,9), how many (8)-digit numbers can be formed without repetition if both (0) and (5) occur, but neither is at an end?

Answer and explanation

Correct answer: (604800)

Place (0) and (5) in the middle (6) positions with order, then fill the remaining positions with other digits. Apply end-position restrictions first.

Related tags

DigitsPosition-RestrictionCountingFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq
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