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Class 11MathematicsPermutations and CombinationsFundamental principle of countingExpert
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How many solutions does (x_1+x_2+x_3+x_4=12) have if (x_1 \ge 2), (x_2) is positive odd, (0 \le x_3 \le 4), and (x_4 \ge 0)?

Answer and explanation

Correct answer: (103)

Convert the restrictions on (x_1) and (x_2) into non-negative variables and take cases for (x_3). For bounded variables, add case counts.

Related tags

Integer-SolutionsCountingRestrictionsFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq
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