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Using the digits (0,1,2,3,4,5,6,7), how many (5)-digit even numbers can be formed without repetition and with the digit (3) included?अंकों (0,1,2,3,4,5,6,7) से (5) अंकों की कितनी सम संख्याएँ बनेंगी जिनमें कोई अंक दोहराया न जाए और अंक (3) अवश्य आए?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (1740)(1740)
First count all even numbers and subtract those without (3). The complement method is efficient for inclusion conditions.पहले सभी सम संख्याएँ गिनें और फिर बिना (3) वाली संख्याएँ घटाएँ। ऐसी शर्तों में पूरक विधि तेज रहती है।
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