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Subjects
Class 11MathematicsPermutations and CombinationsFundamental principle of countingHard
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There are (4) routes from (P) to (Q) and (5) routes from (Q) to (R). A person goes from (P) to (R) and returns to (P), but must not use the same (P) to (Q) route and the same (Q) to (R) route on return. How many ways are possible?

Answer and explanation

Correct answer: (240)

Going has (4 \times 5) ways and returning has (3 \times 4) ways. Multiply independent journey stages.

Related tags

RoutesCountingFundamental-PrincipleFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq
सुधार सुझाएँ / Earn

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