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An admission code has first (2) distinct letters followed by (3) distinct digits. If letters are chosen from (A,B,C,D,E) and digits from (1,2,3,4,5,6), how many codes are possible?

Answer and explanation

Correct answer: (2400)

Letters can be chosen in (5 \times 4) ways and digits in (6 \times 5 \times 4) ways. Multiply independent stages by the fundamental principle.

Related tags

Fundamental-PrincipleCodesPermutationsFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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