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A (5)-character badge has the first (2) places as digits and the next (3) places from (8) letters. The digit sum is even, digits are distinct, and the letters contain (X) exactly once. How many badges are possible?

Answer and explanation

Correct answer: (5040)

Digits are chosen in (40) ways and letters in (3\times7\times6=126) ways. Hence the total is (40\times126=5040).

Related tags

Permutations-And-CombinationsFundamental-PrincipleCountingHardFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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