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Class 11MathematicsPermutations and CombinationsFundamental principle of countingHard
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A four-stage machine sequence has (3,4,5,6) choices respectively. After one machine in the second stage, (2) machines in the third stage cannot be chosen. How many valid sequences are possible?

Answer and explanation

Correct answer: (324)

The second-third stages can be formed in (1\times3+3\times5=18) ways. Then multiply by (3\times6) choices for the first and fourth stages.

Related tags

Permutations-And-CombinationsFundamental-PrincipleCountingHardFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq
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