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In a (5)-place code, the first (2) places are filled by distinct letters from (7) letters, and the last (3) places by distinct digits. The fourth digit must be greater than the fifth digit. How many codes are possible?

Answer and explanation

Correct answer: (15120)

Letters are chosen in (7\times6) ways and digits in (45\times8) ways. Choose the comparison-based pair first.

Related tags

Permutations-And-CombinationsFundamental-PrincipleCountingHardFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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