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A train journey goes from (A) to (D) via (B) and (C). On the outward journey, there are (4,5,6) train choices respectively, and on return the same train cannot be reused on any corresponding segment. In how many ways can the round trip be made?

Answer and explanation

Correct answer: (14400)

For the outward journey there are (4\times5\times6) choices and for return (3\times4\times5) choices. Multiply remaining choices segment by segment.

Related tags

Permutations-And-CombinationsFundamental-PrincipleCountingHardFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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