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A library card has (2) distinct letters from (6) letters, then one separator from (3) separators, and then (2) digits. The sum of the last two digits must be odd and digits may repeat. How many cards are possible?

Answer and explanation

Correct answer: (4500)

For the digit sum to be odd, one digit must be even and the other odd, giving (50) ordered choices. Hence (6\times5\times3\times50=4500).

Related tags

Permutations-And-CombinationsFundamental-PrincipleCountingHardFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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