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A (4)-digit code is formed from digits (1) to (9) with no repeated digit. In the first two digits the first must be smaller, and in the last two digits the third must be larger. How many codes are possible?

Answer and explanation

Correct answer: (756)

For the first two digits there are (\binom{9}{2}) choices, and from the remaining digits (\binom{7}{2}) choices for the last pair. The inequality fixes the order.

Related tags

Permutations-And-CombinationsFundamental-PrincipleCountingHardFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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