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Subjects
Class 11MathematicsPermutations and CombinationsFundamental principle of countingHard
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A coupon selects one each from (4) soups, (3) breads, (5) curries, and (6) drinks. With (2) juice drinks only (3) curries are available, while with other drinks (5) curries are available. How many coupons are possible?

Answer and explanation

Correct answer: (312)

Soups and breads give (4\times3) choices, then drink-curry choices are (2\times3+4\times5=26). Count the dependent pair as one unit.

Related tags

Permutations-And-CombinationsFundamental-PrincipleCountingHardFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq
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