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Subjects
Class 11MathematicsPermutations and CombinationsFundamental principle of countingHard
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An access code contains (2) distinct letters from (6) available letters, (2) symbols from (5) symbols, and (1) odd digit from (5) odd digits. Symbols may repeat. How many codes are possible?

Answer and explanation

Correct answer: (3750)

For letters (6\times5), for symbols (5\times5), and for the digit (5) choices are available. Where repetition is allowed, choices do not decrease.

Related tags

Permutations-And-CombinationsFundamental-PrincipleCountingHardFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq
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