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Subjects
Class 11MathematicsPermutations and CombinationsFundamental principle of countingHard
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There are (7) routes from (X) to (Y), (6) routes from (Y) to (Z), and (4) routes from (Z) to (W). If the first route from (Y) to (Z) is chosen, only (2) later routes are available. How many journeys are possible?

Answer and explanation

Correct answer: (154)

For the special middle route there are (2) choices, and for the other (5) routes there are (4) choices, so (7(2+5\times4)=154). Count the special case separately.

Related tags

Permutations-And-CombinationsFundamental-PrincipleCountingHardFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq
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