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A password has the form letter-digit-letter-digit-letter-digit. The first letter is a vowel, all three letters are distinct, all three digits are distinct, and the last digit is even. How many passwords are possible?

Answer and explanation

Correct answer: (1080000)

For letters we get (5\times25\times24), and for digits (9\times8\times5). Treat the condition on the last position as a separate stage.

Related tags

Permutations-And-CombinationsFundamental-PrincipleCountingHardFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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