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A meal has (6) starters, (8) main dishes, and (5) desserts. With (2) special main dishes only (3) desserts are available, while with the rest (5) are available. How many meal combinations are possible?

Answer and explanation

Correct answer: (216)

Cases depend on the main dish, so (6{(6\times5)+(2\times3)}=216). When a restriction appears, split cases first.

Related tags

Permutations-And-CombinationsFundamental-PrincipleCountingHardFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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