Update

Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है

Subjects
0 reads0 ratings0 helpful

A dictionary index has (3) positions. Each position can contain any of (7) letters. If at least two positions must contain the same letter, how many indices are possible?

Answer and explanation

Correct answer: 133

There are \(7^3=343\) total indices for the three positions. The number of indices with no repeated letter is \(7\times6\times5=210\). Therefore, the number with at least one repeated letter is \(343-210=133\). Option 210 counts only the indices in which all three letters are different. Exam tip: For “at least one repetition” questions, it is usually quickest to subtract the complementary case where all entries are distinct.

Related tags

Fundamental Counting PrincipleComplementary CountingRepeated LettersPermutations And CombinationsClass 11 MathematicsFundamental Principle Of CountingMathematicsClass 11 Mcq

Was this question useful?

No ratings yetWrite a review / Rate this question

Student Reviews

No published reviews yet.

Add Muft Shiksha to your Home Screen

In Safari, tap Share, then Add to Home Screen.