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A locker code has four digits. The first digit cannot be (0), and exactly two digits must be identical while the other two digits are distinct and different from the repeated digit. How many codes are possible?

Answer and explanation

Correct answer: (3888)

Separate cases according to whether the repeated digit is (0). Do not forget the first-place nonzero restriction.

Related tags

PermutationsCombinationsCountingHardFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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