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A vehicle number has two distinct letters followed by four digits. Digits may repeat, but all four digits cannot be identical. How many vehicle numbers are possible?

Answer and explanation

Correct answer: 6493500

There are 26 choices for the first letter and 25 choices for the distinct second letter, giving \(26\times25=650\) letter pairs. The four-digit part has \(10^4=10000\) possible strings. Of these, exactly 10 strings—\(0000,1111,\ldots,9999\)—have all four digits identical, so valid digit strings are \(10000-10=9990\). Hence, the total is \(26\times25\times9990=6493500\). Option B incorrectly includes the 10 forbidden identical-digit strings. Exam tip: Count all cases first and subtract the restricted cases when the restriction is simple.

Related tags

Fundamental Principle Of CountingPermutations And CombinationsCounting PrincipleVehicle NumbersRestriction CountingMathematicsClass 11 Mcq

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