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There are (4) routes from city (A) to (B) and (5) routes from (B) to (C). On return, the same route cannot be used on either segment. How many round trips are possible?

Answer and explanation

Correct answer: 240

For the onward journey, there are 4 choices from A to B and 5 choices from B to C, giving \(4\times5=20\) ways. On the return journey, 4 routes remain from C to B after excluding the route already used, and 3 routes remain from B to A. Hence, the total number of round trips is \(4\times5\times4\times3=240\). Option 120 does not correctly account for the available choices on both return segments. Exam tip: multiply the independent choices for each segment, subtracting a forbidden route only from its own segment.

Related tags

Fundamental Principle Of CountingPermutations And CombinationsRound TripsRoute CountingMultiplication PrincipleMathematicsClass 11 Mcq

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