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A 6-place code has 3 choices for each of the first 2 places, 4 choices for each of the next 2 places, and 2 choices for each of the last 2 places. The two places in the middle pair must have different choices; repetition is allowed elsewhere. How many codes are possible?

Answer and explanation

Correct answer: 432 codes

The first two places allow 3² choices, and the last two allow 2² choices. For the middle pair, there are 4 choices for the first place and 3 different remaining choices for the second. Thus, the total is 3² × 4 × 3 × 2² = 432 codes.

Related tags

Counting PrincipleRestricted RepetitionClass 11Fundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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