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A code consists of 3 distinct digits followed by 2 distinct letters. The available digits are 0, 1, 2, 3, 4, 5, and 6, and the available letters are P, Q, R, S, and T. How many codes are possible?

Answer and explanation

Correct answer: 4200 codes

The three digit positions can be filled in 7 × 6 × 5 ways, since digits cannot repeat. The two letter positions can be filled in 5 × 4 ways. The total is 7 × 6 × 5 × 5 × 4 = 4200 codes.

Related tags

Counting PrinciplePermutationsClass 11Fundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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